I can not figure out how to switch string 2019/9/8 to date 2019/09/08.
So far I’ve tried to use cell splitter to split 2019/9/8 to 3 columns which are year (like 2019), month (like 9) and day(like 8). Then I use rule engine to create a new column which is 0. Then I use string manipulation to join 0 and month, 0 and day. So it looks like 2019, 09, 08. But date like 2019/11/12 will looks like 2019, 011, 012. So I tried to keep last 2 characters of month and day column before join them together. And I haven’t figure out how.
Do anybody know how to keep the last 2 characters of a column?
And is there any easier way to transfer from string 2019/9/8 to date 2019/09/08?
With the String to Date/Time (legacy) you can transform your date-string to a real date-field.
And with String Manipulation node it’s possible to extract the last two characters of your string.
See this last2.knwf (17.2 KB)
Thank you so much!! Your answer is super helpful!
Hi @Jocelyn -
Here’s another suggestion for you. Since this question comes up fairly regularly - how do I deal with string-dates that don’t have leading zeroes, without using a legacy node? - I thought I would post a workflow on the Hub about it. You can get there with very few nodes once you know the trick, which is basically to set the format to something like:
Note the single M and d in the format, which will actually handle double digit months and days too. Anyway, here’s the workflow:
Thanks so much sir. It’s very practical!!
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