Hello Knimers,
How could I replace the space characters on 0 between the smybols in the following string?
DEBUG ( 0) [ 811] 03/01/2021 06:36:25 Received line: BREQ
Thank you in advance!
Roland
Hello Knimers,
How could I replace the space characters on 0 between the smybols in the following string?
DEBUG ( 0) [ 811] 03/01/2021 06:36:25 Received line: BREQ
Thank you in advance!
Roland
Hi @rolandnemeth ,
I’m not sure I understood correctly. do you want to get to the following string?
DEBUG ( 0) [0811] 03/01/2021 06:36:25 Received line: BREQ
If yes, you can do this by using “String Manipulation” with “regexReplace” like this:
Hi @FtmhRahimi,
Thanks for the fast response.
Exactly, if the number of space characters is only 1 between the square brackets.
I mean (have not tested) your solution works, if only 1 space character can be found between the brackets.
But the situation is not so simple, the number of space characters can be more then 1 inside the bracket.
Best regards,
Roland
Hi @rolandnemeth,
So just add a “+” after the white space char in @FtmhRahimi’s regex:
regexReplace($text$, "\\[\\s+(\\d)\\]", "[$1]")
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