Good morning,
I am not practical with colum expression. I am creating a column named “Number_2”.
I want this column to be 1 or the value in cell above of the same column ("Number_2,-1) plus 1. I receive an error of missing column (the one that I am creating).
I would expect the column to be recognize as it should be iterative.
Is there any way to refer to row n-1 of the same column that I am creating?
Hey there,
right now it is not possible to refer to the column you are creating in the expression you are creating the column with.
If I remember correctly in the release event it was mentioned it is on the roadmap to enable this in the new Expressions node in the future.
A work around could be to add the column generically and then send it into a recursive loop that processes one row at a time…
Thanks for the explanation. I have used a workaround with group looping and it worked.
Note that the honorable @takbb found that CE does have some memory capability as well but might not be worth the effort to get it properly running if there’s an easier alternative.
wow I actually did not know that. Then let me rephrase - I guess officially this is not working, but there are ways to make it work if you know how to (and am OK to spend some extra effort).
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